[tied] Re: PIE i- and u-stems again

From: tgpedersen
Message: 47432
Date: 2007-02-13

> >> NA *g^á:n-un > *g^ónur
> >> G *g^a:n-ún-a:s > *g^en&wós > *g^énwos
> >> or, with early stress-shift:
> >> G > *g^enw&nós > *g^énunos
> >> L *g^a:n-ún-a > *g^enéw-i > *g^énui
> >> I *g^a:n-un-éh1 > *g^enunéh1 > *g^énuneh1
> >> du.
> >> NA *g^á:n-un-ih1 > *g^ónunih1 (cf. Skt. januni:, Toch.B
> >> keni:ne)
> >
> >Is this *-ur/*-un heteroclitic matched with similar *-ir/*-in and
> >*-ar/*-an heteroclitics?
>
> Sure. The *-[C]ar/*-[C]an heteroclitics are the normal
> -r/-n heteroclitics [after zero grade]. The *-[C]ir/*-[C]in
> heteroclitics are the i/n-stems of Sanskrit (áks.i, aks.nás
> "eye", ásthi, asthnás "bone", dádhi, dadhnás "curds",
> sákthi, sakthná: "thigh"). *potis (Toch. petso reflects the
> old nominative *pótyo:n) is probably a non-neuter member of
> this same group.
>
> >If so, is the *-r/*-n part detachable from the stem in *-u, *-i and
*-a?
>
> No. *-un- is a suffix. Suffixes are (C)VC(C).
>
> >How would you account for Latin pecus, pecoris and pecus, pecudis?
> >If your *-ur/*-un stem is like the usual heteroclitics, its
> >consonant would alternate with more than r/n
>
> The r/n alternation is simply the result of a soundlaw:
> n > r / _# (but n > n / m(V)_# ).
>
> There is an ancient alternation n ~ t (e.g. in the plural
> morpheme **-an ~ **-atV), which is not limited to PIE. This
> may be relevant to the connection between n/r-stems and
> s-stems, but I don't know how.
>
> I can't do anything with pecus, pecudis

How about a 'pronominal ending' *pek^ud-. If Slavic can do it, so can
Latin. Which reminds me

http://www.hhhh.org/perseant/libellus/aides/allgre/allgre.105.html

These variants I haven't seen before. We might have nom. *pek^ud ->
pecú, abl. *pek^ud -> pecú. It meshes nicely with my idea that the
pronominal nNA -d is an old partitive = ablative. How would you
explain them?


Torsten