[tied] Re: PIE 'brow'

--- In cybalist@yahoogroups.com, Miguel Carrasquer <mcv@...> wrote:

> >Question: is the Lithuanian "z^t" reflected as "zd" in Slavic?
>
> There is no z^t. The root is bré:z^-. -ti is the
> infinitive ending (= Slavic -ti [> -t' > -t]).
>
> =======================
> Miguel Carrasquer Vidal
> mcv@...

Thank you Miguel. How is to explain in this case OCS "brazda"?

Alex