Re: [tied] IE vowels

On Sat, 07 Jun 2003 00:58:00 +0000, Glen Gordon <glengordon01@...>
wrote:

>
>Miguel:
>>So you're saying that *q arose from **k in the neighbourhood of **a.
>
>Yes, this started in IndoTyrrhenian.
>
>
>>Wouldn't it be simpler to take *q as basic
>
>No. It requires an extra phoneme we don't need. That's wasteful.
>
>Working back to Mid IE, *q always seems to be next to *a.

No it doesn't.

>The word *qreux- appears to be a deverbal noun, composed
>of a stem *qreu- and *-x- (transitive).

It's actually a root *qreux- and a suffix *-(V)s.

>The stem *qreu- can be
>further broken down as an extension of a verb *qar-/*qor-
>which should be derived from Mid IE *kar-. Originally when
>this root alternated during ablaut, *q alternated with *k.

What ablaut? The ablaut is NA *kréw&2-s (Skt. kravís, Grk. kréas), Obl.
*kruh2-ás-/*kruh2-s-ós (-> OCS kry), coll. *kruh2-ó:s (Lat. cruor) ~
*kruh2-ás-. Nowhere is there a vowel between *k and *r.

>However, the root eventually sided with *q in all forms
>because its default form was with *[q] (since it was in
>the a-grade). Likewise, stems where the default form was in
>the e-grade developped *k throughout its paradigm, rather
>than *q. So *kwon- represents how a consonant cluster
>normally develops because it was created when *q still
>alternated with *k, which is why we seldom ever see *q
>in a consonant cluster.

We see *q in a consonant cluster all the time. Just look under kl-, kr- or
kw- in Pokorny, or in a Sanskrit dictionary.

=======================
Miguel Carrasquer Vidal
mcv@...