Re: [tied] Re: Latin barba in disaccord with Grimm's Law?

From: Miguel Carrasquer
Message: 45137
Date: 2006-06-26

On Mon, 26 Jun 2006 12:02:42 -0700 (PDT), Sean Whalen
<stlatos@...> wrote:

>--- Miguel Carrasquer <mcv@...> wrote:
>
>> No, I'm saying there is no o > a in Armenian.

What there is in Armenian is a marked tendency to favour the
oblique (weak) stem (cf. for instance barjr < *bherg^h- ~
*bhr.g^h-, etc.):

> What about
>
>akn vs oculus L

G. *&3kW-mn.(t)-ós (= Grk. ómmatos) => *ak`mánoh > akan
(with loss of aspiration of k`). The plural is based on the
dual *&3kW-íh1 > ac^` + -k`. Olsen 170.

>ayn vs oino-/e:- Gk

Not sure what the connection is supposed to be. The Arm.
demonstratives ays, ayd, ayn (besides sa, da, na, -s, -d, -n
and soyn, doyn, noyn) consist of the basic elements *k^(i),
*t(o) and *(-)no. The origin of ay- is unclear.

>aytnum vs oidos- Gk

Greek oideo: has o-grade (causative-iterative), and oi~dos
is an o-grade thematic noun. The Armenian verb is based on
the e-grade root (or zero-grade) *h2eid- ~ *h2id- (> ayt-),
LIV 258.

>atamn vs odont- Gk

Zero grade *&1dn.(t)-mn.t-ós > atamán (G). Cf. Olsen 505.

>ateam vs odium, o:di: L

Zero-grade *&3d- plus stressed formative -eám.

>garun vs vasara Lith (o>a in Lith)

*wesr > ge(h)ar > gar + -onto- > -un. Olsen 41.

> I suppose you also would have to say h2 and h3 merge
>before h2>a. It's possible by itself, but makes some
>changes strange (assimilation in enuma-/onuma- can't
>account for anun).

*&1noh3mn > anu(w)n (/m/ > /w/ before or after /o:/, Olsen
132). Or perhaps zero-grade *&nh3mn. (= Slavic *inmin >
jImeN) with *nh3 > no:, as in Greek.

>Do you have any cases of a>o later (and e>o)?

Alleged cases of e > a are, amongst others:

tasn, not from *dek^m. but from *dk^omt > t(a)sun > tasn
(this one's mine).

caLr (G. caLu), from a combination of nom. g^élh2o:s >
*ceLu, and oblique *g^l.h2sós > *caL-. Olsen 169.

asr (G. asu), from *pek^ur (> *esr) [or *pok^u(r) (> *osr)],
and oblique *pk^-u- (> *h(a)su- > asu-). Olsen 202.

>How do you derive k'ayr from *swesor- (any
>analogy)?

Straightforward: sweso:r > k`e(h)ur > k`oyr (with the normal
development *eu > oy).

=======================
Miguel Carrasquer Vidal
mcv@...